(x+1)^2=(x+1)(x-2)

Solution for (x+1)^2=(x+1)(x-2) equation:

(x+1)^2=(x+1)(x-2)

We move all terms to the left:

(x+1)^2-((x+1)(x-2))=0

We multiply parentheses ..

-((+x^2-2x+x-2))+(x+1)^2=0


We calculate terms in parentheses: -((+x^2-2x+x-2)), so:

(+x^2-2x+x-2)

We get rid of parentheses

x^2-2x+x-2

We add all the numbers together, and all the variables

x^2-1x-2

Back to the equation:

-(x^2-1x-2)


We get rid of parentheses

-x^2+1x+(x+1)^2+2=0

We add all the numbers together, and all the variables

-1x^2+x+(x+1)^2+2=0

We move all terms containing x to the left, all other terms to the right

-1x^2+x+(x+1)^2=-2